cho hpt 2x^2 - 3/y^2 + x/y =12 và 6xy^2 + x^2y = 12y^2 + 6y+x
Những câu hỏi liên quan
Phân tích đa thức thành nhân tử:
+)5x2y2+15x2+30xy2
+)(x-2)(x-3)+4-x2
+)x2-7x+12
+)x3-2x2y+xy2-9x
+)x2-25+y2+2xy
+)x2-x-12
+)5x25xy-x-y
+)12y(2x-5)+6xy(5-2x)
+)16x2+24x-8xy-6y+y2
+)(x+3)(x+6)(x+9)(x+12)+81
a: \(=5x\left(xy^2+3x+6y^2\right)\)
b: \(=\left(x-2\right)\left(x+3\right)-\left(x-2\right)\left(x+2\right)=\left(x-2\right)\left(x+3-x-2\right)=\left(x-2\right)\)
c: \(=\left(x-3\right)\left(x-4\right)\)
d: \(=x\left(x^2-2xy+y^2-9\right)\)
=x(x-y-3)(x-y+3)
e: \(=\left(x+y\right)^2-25=\left(x+y+5\right)\left(x+y-5\right)\)
f: \(=\left(x-4\right)\left(x+3\right)\)
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1/ Giải hpt = p đặt ẩn phụ : a,\(\left\{{}\begin{matrix}\left(x+y\right)^3+y=5\\3\left(x+y\right)^3-22xy+21=11x^2+12y^3\end{matrix}\right.\)
b,\(\left\{{}\begin{matrix}81x^3y^2-81x^2y^2+33xy^2-29y^2=4\\25y^3+9x^2y^3-6xy^3-4y^2=24\end{matrix}\right.\)
1. giải hpt 5(x^2+y^2)=6xy+2 và 2x^2+3x=2y^2+y+3
cần gấp
\(\left\{{}\begin{matrix}5x^2+5y^2-6xy=2\\2x^2+3x-2y^2-y=3\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}5x^2+5y^2-6xy=2\\4x^2+6x-4y^2-2y=6\end{matrix}\right.\)
\(\Rightarrow9x^2+y^2-6xy+6x-2y+1=9\)
\(\Leftrightarrow\left(3x-y+1\right)^2=9\)
\(\Leftrightarrow\left[{}\begin{matrix}3x-y+1=3\\3x-y+1=-3\end{matrix}\right.\)
Đến đây chia 2 trường hợp và thế vào 1 trong 2 pt để giải
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giải hpt:
\(\left\{{}\begin{matrix}2x^2-3y^2+xy=12\\6x+x^2y=12+6y+y^2x\end{matrix}\right.\)
\(\left\{{}\begin{matrix}\left(x-y\right)\left(2x+3y\right)=12\\\left(x-y\right)\left(xy+6\right)=12\end{matrix}\right.\)
Trừ trên cho dưới:
\(\left(x-y\right)\left(2x+3y-xy-6\right)=0\Leftrightarrow\left(x-y\right)\left(x-3\right)\left(2-y\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=y\\x=3\\y=2\end{matrix}\right.\)
TH1: \(x=y\) thay vào pt đầu ta được \(0=12\) (vô nghiệm)
TH2: \(x=3\Rightarrow-3y^2+3x+6=0\Rightarrow\left[{}\begin{matrix}y=-1\\y=2\end{matrix}\right.\)
TH3: \(y=2\Rightarrow2x^2+2x-24=0\Rightarrow\left[{}\begin{matrix}x=3\\x=-4\end{matrix}\right.\)
Vậy pt có 3 cặp nghiệm \(\left(x;y\right)=\left(3;-1\right);\left(3;2\right);\left(-4;2\right)\)
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8X^2 - 6XY( 2X-Y) + 6X= 2Y^3 -6Y^2+ 18Y-14
Y^2 - 6Y + 5 + căn bậc ba (Y+1) (X^2 + 8) = 0
1) Tìm x, y, za) 9x2 +y2 + 2z2 – 18x +4z – 6y +20 0b) 5x2 +5y2 +8xy+2y – 2x+2 0c) 5x2 +2y2 + 4xy – 2x + 4y +5 0d) x2 + 4y2 + z2 2x + 12y – 4z – 14e) x2 +y2 – 6x + 4y +2 0 2) Phân tích đa thức thành nhân tửa) 3xy2 – 3x3 – 6xy +3xb) 3x2 + 11x + 6c) –x3 – 4xy2 + 4x2y +16xd) xz – x2 – yz +2xy – y2e) 4x2 – y2 – 6x + 3yf) X4 – x3 – 10x2 + 2x +4g) (x3 – x2 + x)(121 – 25y2 – 10y) – (x3 – x2 + x) – (121 – 25y2 – 10y) +1h) X4 – 14x3 + 71x2 – 154x + 120Giúp mik vs cần gấp!!!
Đọc tiếp
1) Tìm x, y, z
a) 9x2 +y2 + 2z2 – 18x +4z – 6y +20 = 0
b) 5x2 +5y2 +8xy+2y – 2x+2 = 0
c) 5x2 +2y2 + 4xy – 2x + 4y +5 = 0
d) x2 + 4y2 + z2 =2x + 12y – 4z – 14
e) x2 +y2 – 6x + 4y +2= 0
2) Phân tích đa thức thành nhân tử
a) 3xy2 – 3x3 – 6xy +3x
b) 3x2 + 11x + 6
c) –x3 – 4xy2 + 4x2y +16x
d) xz – x2 – yz +2xy – y2
e) 4x2 – y2 – 6x + 3y
f) X4 – x3 – 10x2 + 2x +4
g) (x3 – x2 + x)(121 – 25y2 – 10y) – (x3 – x2 + x) – (121 – 25y2 – 10y) +1
h) X4 – 14x3 + 71x2 – 154x + 120
Giúp mik vs cần gấp!!!
\(a,9x^2+y^2+2z^2-18x+4z-6y+20=0\\ \Leftrightarrow9\left(x-1\right)^2+\left(y-3\right)^2+2\left(z+1\right)^2=0\\ \Leftrightarrow\left\{{}\begin{matrix}x=1\\y=3\\z=-1\end{matrix}\right.\)
\(b,5x^2+5y^2+8xy+2y-2x+2=0\\ \Leftrightarrow4\left(x+y\right)^2+\left(x-1\right)^2+\left(y+1\right)^2=0\\ \Leftrightarrow\left\{{}\begin{matrix}x=-y\\x=1\\y=-1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\y=-1\end{matrix}\right.\)
\(c,5x^2+2y^2+4xy-2x+4y+5=0\\ \Leftrightarrow\left(2x+y\right)^2+\left(x-1\right)^2+\left(y+2\right)^2=0\\ \Leftrightarrow\left\{{}\begin{matrix}2x=-y\\x=1\\y=-2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\y=-2\end{matrix}\right.\)
\(d,x^2+4y^2+z^2=2x+12y-4z-14\\ \Leftrightarrow\left(x-1\right)^2+\left(2y-3\right)^2+\left(z+2\right)^2=0\\ \Leftrightarrow\left\{{}\begin{matrix}x=1\\y=\dfrac{3}{2}\\z=-2\end{matrix}\right.\)
\(e,x^2+y^2-6x+4y+2=0\\ \Leftrightarrow\left(x-3\right)^2+\left(y+2\right)^2=11\)
Pt vô nghiệm do ko có 2 bình phương số nguyên có tổng là 11
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e: Ta có: \(x^2-6x+y^2+4y+2=0\)
\(\Leftrightarrow x^2-6x+9+y^2+4y+4-11=0\)
\(\Leftrightarrow\left(x-3\right)^2+\left(y+2\right)^2=11\)
Dấu '=' xảy ra khi x=3 và y=-2
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1) Tìm x, y, za) 9x2 +y2 + 2z2 – 18x +4z – 6y +20 0b) 5x2 +5y2 +8xy+2y – 2x+2 0c) 5x2 +2y2 + 4xy – 2x + 4y +5 0d) x2 + 4y2 + z2 2x + 12y – 4z – 14e) x2 +y2 – 6x + 4y +2 0 2) Phân tích đa thức thành nhân tửa) 3xy2 – 3x3 – 6xy +3xb) 3x2 + 11x + 6c) –x3 – 4xy2 + 4x2y +16xd) xz – x2 – yz +2xy – y2e) 4x2 – y2 – 6x + 3yf) X4 – x3 – 10x2 + 2x +4g) (x3 – x2 + x)(121 – 25y2 – 10y) – (x3 – x2 + x) – (121 – 25y2 – 10y) +1h) X4 – 14x3 + 71x2 – 154x + 120Giúp mik với mik đang cần rất gấp ạ!!!
Đọc tiếp
1) Tìm x, y, z
a) 9x2 +y2 + 2z2 – 18x +4z – 6y +20 = 0
b) 5x2 +5y2 +8xy+2y – 2x+2 = 0
c) 5x2 +2y2 + 4xy – 2x + 4y +5 = 0
d) x2 + 4y2 + z2 =2x + 12y – 4z – 14
e) x2 +y2 – 6x + 4y +2= 0
2) Phân tích đa thức thành nhân tử
a) 3xy2 – 3x3 – 6xy +3x
b) 3x2 + 11x + 6
c) –x3 – 4xy2 + 4x2y +16x
d) xz – x2 – yz +2xy – y2
e) 4x2 – y2 – 6x + 3y
f) X4 – x3 – 10x2 + 2x +4
g) (x3 – x2 + x)(121 – 25y2 – 10y) – (x3 – x2 + x) – (121 – 25y2 – 10y) +1
h) X4 – 14x3 + 71x2 – 154x + 120
Giúp mik với mik đang cần rất gấp ạ!!!
Tim x,y biet:
1)x^2-2x+5+y^2-4y0
2)4x^2+y^2-20x+26-2y0
3)x^2+4y^2+13-6x-8y0
4)4x^2+4x-6y+9x^2+20
5)x^2+y^2+6x-10y+340
6)25x^2-10x+9y^2-12y+50
7)x^2+9y^2-10x-12y+290
89x^2+12x+4y62+8y+80
9)4x^2+9y^2+20x-6y+260
10)3x^2+3y^2+6x-12y+150
11)x^2+4y^2+4x-4y+50
12)4x^2-12x+y^2-4y+130
13)x^2+y^2+2x-6y+100
14)4x^2+9y^2-4x+6y+20
15)y^2+2y+5-12x+9x^20
16)x^2+26+6y+9y^2-10x0
17)10-6x+12y+9x^2+4y^20
18)16x^2+5+8x-4y+y^20
19)x^2+9y^2+4x+6y+50
20)5+9x^2+9y^2+6y-12x0
21)x^2+20+9y62+8x-12y0...
Đọc tiếp
Tim x,y biet:
1)x^2-2x+5+y^2-4y=0
2)4x^2+y^2-20x+26-2y=0
3)x^2+4y^2+13-6x-8y=0
4)4x^2+4x-6y+9x^2+2=0
5)x^2+y^2+6x-10y+34=0
6)25x^2-10x+9y^2-12y+5=0
7)x^2+9y^2-10x-12y+29=0
89x^2+12x+4y62+8y+8=0
9)4x^2+9y^2+20x-6y+26=0
10)3x^2+3y^2+6x-12y+15=0
11)x^2+4y^2+4x-4y+5=0
12)4x^2-12x+y^2-4y+13=0
13)x^2+y^2+2x-6y+10=0
14)4x^2+9y^2-4x+6y+2=0
15)y^2+2y+5-12x+9x^2=0
16)x^2+26+6y+9y^2-10x=0
17)10-6x+12y+9x^2+4y^2=0
18)16x^2+5+8x-4y+y^2=0
19)x^2+9y^2+4x+6y+5=0
20)5+9x^2+9y^2+6y-12x=0
21)x^2+20+9y62+8x-12y=0
22)x^2=4y+4y^2+26-10x=0
23)4y^2+34-10x+12y+x^2=0
24)-10x+y^2-8y+x^2+41=0
25)x^2+9y^2-12y+29-10x=0
26)9x^2+4y^2+4y+5-12x=0
27)4y^2-12x+12y+9x^2=13=0
28)4x^2+25-12x-8y+y^2=0
29)x62+17+4y^2+8x+4y=0
30)4y^2+12y+25+8x+x^2=0
31)x^2+20+9y^2+8x-12y=0
giup mk voi minh can gap ak, cam on cac ban
giải hệ phương trình:
1, \(\left\{{}\begin{matrix}2+6y=\frac{x}{y}-\sqrt{x-2y}\\\sqrt{x+\sqrt{x-2y}}=x+3y-2\end{matrix}\right.\)
2, \(\left\{{}\begin{matrix}x^2+y^2+xy+1=4y\\y\left(x+y\right)^2=2x^2-7y+2\end{matrix}\right.\)
3, \(\left\{{}\begin{matrix}x^2\left(y+1\right)=6y-2\\x^4y^2+2x^2y^2+y\left(x^2+1\right)=12y^2-1\end{matrix}\right.\)
